5/4(x^2+4x+4)+5/4(x^2-4x+4)

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Solution for 5/4(x^2+4x+4)+5/4(x^2-4x+4) equation: 


x in (-oo:+oo)

(5/4)*(x^2+4*x+4)+(5/4)*(x^2-(4*x)+4) = 0

(5/4)*(x^2+4*x+4)+(5/4)*(x^2-4*x+4) = 0

5/4*(x^2+4*x+4)+5/4*(x^2-4*x+4) = 0

5/4*(x^2+4*x+4)+5/4*(x^2-4*x+4) = 0

5/2*x^2+10 = 0

5/2*x^2+10 = 0

5/2*x^2 = -10 // : 5/2

x^2 = -4

x belongs to the empty set

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